习题 31: 作出决定

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这本书的上半部分你打印了一些东西,而且调用了函数,不过一切都是直线式进行的。 你的脚本从最上面一行开始,一路运行到结束,但其中并没有决定程序流向的分支点。 现在你已经学了 if, else, 和 elif ,你就可以开始创建包含条件判断 的脚本了。

上一个脚本中你写了一系列的简单提问测试。这节的脚本中,你将需要向用户提问, 依据用户的答案来做出决定。把脚本写下来,多多鼓捣一阵子,看看它的工作原理是 什么。

print "You enter a dark room with two doors.  Do you go through door #1 or door #2?"

door = raw_input("> ")

if door == "1":
    print "There's a giant bear here eating a cheese cake.  What do you do?"
    print "1. Take the cake."
    print "2. Scream at the bear."

    bear = raw_input("> ")

    if bear == "1":
        print "The bear eats your face off.  Good job!"
    elif bear == "2":
        print "The bear eats your legs off.  Good job!"
    else:
        print "Well, doing %s is probably better.  Bear runs away." % bear

elif door == "2":
    print "You stare into the endless abyss at Cthulhu's retina."
    print "1. Blueberries."
    print "2. Yellow jacket clothespins."
    print "3. Understanding revolvers yelling melodies."

    insanity = raw_input("> ")

    if insanity == "1" or insanity == "2":
        print "Your body survives powered by a mind of jello.  Good job!"
    else:
        print "The insanity rots your eyes into a pool of muck.  Good job!"

else:
    print "You stumble around and fall on a knife and die.  Good job!"

这里的重点是你可以在“if 语句”内部再放一个“if 语句”。这是 一个很强大的功能,可以用来创建嵌套(nested)的决定,其中的一个分支将引向另一个 分支的子分支。

你需要理解 if 语句 包含 if 语句 的概念。做一下加分习题,这样你会确信 自己真正理解了它们。

What You Should See

我在玩一个小冒险游戏,我玩的水平不怎么好:

$ python ex31.py
You enter a dark room with two doors.  Do you go through door #1 or door #2?
>  1
There's a giant bear here eating a cheese cake.  What do you do?
1. Take the cake.
2. Scream at the bear.
>  2
The bear eats your legs off.  Good job!

Study Drills

  1. 为游戏添加新的部分,改变玩家做决定的位置。尽自己的能力扩展这个游戏,不过别把游戏弄得 太怪异了。
  2. 写一个全新的小游戏,也许你不喜欢我这个,那你就整一个自己的。这是你的电脑,你想干哈干哈。

Common Student Questions

Can you replace elif with a sequence of if-else combinations?
You can in some situations, but it depends on how each if/else is written. It also means that Python will check every if-else combination, rather than just the first false ones like it would with if-elif-else. Try to make some of these to figure out the differences.
How do I tell if a number is between a range of numbers?
You have two options: Use 0 < x < 10 or 1 <= x < 10, which is classic notation, or use x in range(1, 10).
What if I wanted more options in the if-elif-else blocks?
Add more elif blocks for each possible choice.

Copyright (C) 2010 by
Author: Zed Shaw
Translator:Zander Wong

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